-[3x+(4x+1)]=2-(3x+9)

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Solution for -[3x+(4x+1)]=2-(3x+9) equation:


Simplifying
-1[3x + (4x + 1)] = 2 + -1(3x + 9)

Reorder the terms:
-1[3x + (1 + 4x)] = 2 + -1(3x + 9)

Remove parenthesis around (1 + 4x)
-1[3x + 1 + 4x] = 2 + -1(3x + 9)

Reorder the terms:
-1[1 + 3x + 4x] = 2 + -1(3x + 9)

Combine like terms: 3x + 4x = 7x
-1[1 + 7x] = 2 + -1(3x + 9)
[1 * -1 + 7x * -1] = 2 + -1(3x + 9)
[-1 + -7x] = 2 + -1(3x + 9)

Reorder the terms:
-1 + -7x = 2 + -1(9 + 3x)
-1 + -7x = 2 + (9 * -1 + 3x * -1)
-1 + -7x = 2 + (-9 + -3x)

Combine like terms: 2 + -9 = -7
-1 + -7x = -7 + -3x

Solving
-1 + -7x = -7 + -3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3x' to each side of the equation.
-1 + -7x + 3x = -7 + -3x + 3x

Combine like terms: -7x + 3x = -4x
-1 + -4x = -7 + -3x + 3x

Combine like terms: -3x + 3x = 0
-1 + -4x = -7 + 0
-1 + -4x = -7

Add '1' to each side of the equation.
-1 + 1 + -4x = -7 + 1

Combine like terms: -1 + 1 = 0
0 + -4x = -7 + 1
-4x = -7 + 1

Combine like terms: -7 + 1 = -6
-4x = -6

Divide each side by '-4'.
x = 1.5

Simplifying
x = 1.5

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